2n(n+1)-n^2=2n^2+2n-n^2=n^2+2n

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Solution for 2n(n+1)-n^2=2n^2+2n-n^2=n^2+2n equation: 



2n(n+1)-n^2=2n^2+2n-n^2=n^2+2n

We move all terms to the left:

2n(n+1)-n^2-(2n^2+2n-n^2)=0

We add all the numbers together, and all the variables

-1n^2-(2n^2+2n-n^2)+2n(n+1)=0

We multiply parentheses

-1n^2-(2n^2+2n-n^2)+2n^2+2n=0

We get rid of parentheses

-1n^2-2n^2+n^2+2n^2-2n+2n=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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